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For the reaction , N2H4+H2rightarrow2NH3...

For the reaction , `N_2H_4+H_2rightarrow2NH_3`, bond energies are given as : `B.E(N-N)=x`,`B.E(H-H)=y` ,`BE(N-H)=z`, then `DeltaH_f°(NH_3)` is

A

`x-2z-y`

B

`x/2-y/2-z`

C

`z-x/2+y/2`

D

Cannot be calculated

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AAKASH INSTITUTE ENGLISH-TEST 5-EXAMPLE
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