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If delta0 of Ni^(2+) in presence of NH3 ...

If `delta_0` of `Ni^(2+)` in presence of `NH_3` is `100 KJ` then that for `Pd^(2+)` will be

A

`200 KJ`

B

`250 KJ`

C

`100 KJ`

D

`150 KJ`

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