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Bis will be used in the meaning as...

Bis will be used in the meaning as

A

`[Cr(NH_3)_2(en)_2]^(3+)`

B

`[Cr(NH_3)_(CN)_2Br_2]^(-)`

C

`[CrCl_2F_2Br_2]^(3-)`

D

`[Cr(NH_3)_2(en)Cl_2]^(+)`

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