Home
Class 12
PHYSICS
A conductor having cubold shape has dime...

A conductor having cubold shape has dimensions in ratio 1: 2:5, the ratio of maximum to minimum resistance across two opposite faces is

A

A. 0

B

B. `5:1`

C

C. `25:1`

D

D. `10:1`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the ratio of maximum to minimum resistance across two opposite faces of a cuboidal conductor with dimensions in the ratio 1:2:5, we can follow these steps: ### Step 1: Define the Dimensions Let the dimensions of the cuboid be: - Length (L) = 1x - Breadth (B) = 2x - Height (H) = 5x ### Step 2: Identify the Faces The cuboid has three pairs of opposite faces: 1. Faces with dimensions (Length x Height) = (1x x 5x) 2. Faces with dimensions (Breadth x Height) = (2x x 5x) 3. Faces with dimensions (Length x Breadth) = (1x x 2x) ### Step 3: Calculate Minimum Resistance The minimum resistance will be across the faces with the smallest area. The area of the faces with dimensions (1x x 2x) is: \[ A_{min} = 1x \times 2x = 2x^2 \] Using the formula for resistance: \[ R = \frac{\rho L}{A} \] Where: - \( \rho \) = resistivity of the material - \( L \) = thickness of the conductor (which we take as the other dimension, here it will be 5x) Thus, the minimum resistance \( R_{min} \) is: \[ R_{min} = \frac{\rho (5x)}{2x^2} = \frac{5\rho}{2x} \] ### Step 4: Calculate Maximum Resistance The maximum resistance will be across the faces with the largest area. The area of the faces with dimensions (2x x 5x) is: \[ A_{max} = 2x \times 5x = 10x^2 \] Thus, the maximum resistance \( R_{max} \) is: \[ R_{max} = \frac{\rho (1x)}{10x^2} = \frac{\rho}{10x} \] ### Step 5: Calculate the Ratio of Maximum to Minimum Resistance Now, we can find the ratio of maximum resistance to minimum resistance: \[ \frac{R_{max}}{R_{min}} = \frac{\frac{\rho}{10x}}{\frac{5\rho}{2x}} = \frac{\rho}{10x} \times \frac{2x}{5\rho} \] The \( \rho \) and \( x \) cancel out: \[ \frac{R_{max}}{R_{min}} = \frac{2}{50} = \frac{1}{25} \] Thus, the ratio of maximum to minimum resistance is: \[ R_{max} : R_{min} = 25 : 1 \] ### Final Answer The ratio of maximum to minimum resistance across two opposite faces is **25:1**. ---
Promotional Banner

Topper's Solved these Questions

  • TEST 1

    AAKASH INSTITUTE ENGLISH|Exercise EXERCISE|21 Videos
  • TEST 3

    AAKASH INSTITUTE ENGLISH|Exercise EXAMPLE|74 Videos

Similar Questions

Explore conceptually related problems

In YDSE ratio of width of slit is 4:1 , then ratio of maximum to minimum intensity

In YDSE ratio of width of slit is 4:1 , then ratio of maximum to minimum intensity

If two light waves having same frequency have intensity ratio 4:1 and they interfere, the ratio of maximum to minimum intensity in the pattern will be

All the edges of a block with parallel faces are unequal. Its longest edge is twice its shortest edge. The ratio of the maximum to minimum resistance between parallel faces is.

The ratio of the maximum value to minimum value of 2cos^(2)theta+cos theta+1 is :

Ratio of amplitude for two wave is 1:5.Find the ratio of maximum Intensity to minimum intensity.

If the ratio of amplitude of two waves is 4:3 , then the ratio of maximum and minimum intensity is

Ratio of amplitude for two wave is 1:4 .Find the ratio of maximum intensity to minimum intensity.

Ratio of amplitude for two wave is 1:3 .Find the ratio of maximum intensity to minimum intensity.

A conductor with rectangular cross section has dimensions (axx2axx4a) as shown in figure. Resistance across AB is x, across CD is y and across EF is z. Then

AAKASH INSTITUTE ENGLISH-TEST 2-Exercise
  1. In a region the potential is represented by V(x, y, z) = 8x - 6xyz - 6...

    Text Solution

    |

  2. A parallel plate capacitor is charged to a potential difference of 10 ...

    Text Solution

    |

  3. A conductor having cubold shape has dimensions in ratio 1: 2:5, the ra...

    Text Solution

    |

  4. Two resistors of resistances 10 Omega and 40 Omega are connected with ...

    Text Solution

    |

  5. The resistance in two arms of the meter bridge is 10 Omega and x respe...

    Text Solution

    |

  6. The magnetic field Intensity at the point o of a loop carrying current...

    Text Solution

    |

  7. A beam of electrons is moving with uniform velocity in a region having...

    Text Solution

    |

  8. A bar magnet hung by a insulating thread In a uniform horizontal magne...

    Text Solution

    |

  9. Area under magnetic field induction and magnetizing field intensity (B...

    Text Solution

    |

  10. An objective of a telescope has diameter 250 cm. The limit of resoluti...

    Text Solution

    |

  11. In the given resonating circuit the reading of voltmeter V is 314 volt...

    Text Solution

    |

  12. The rms value of electric field of a light at a point coming from the ...

    Text Solution

    |

  13. A parallel beam of light consisting of red and blue colour is incident...

    Text Solution

    |

  14. The interference pattern is obtained with two coherent light sources o...

    Text Solution

    |

  15. The photoelectric threshold wavelength of a metal is 300 nm. The maxim...

    Text Solution

    |

  16. The hydrogen atom in ground state is excited by a monochromatic radiat...

    Text Solution

    |

  17. A radioactive element, U92^238 undergoes successive radioactive decay ...

    Text Solution

    |

  18. A radioactive sample is decayed 20% in one day. After next two days, t...

    Text Solution

    |

  19. If the voltage between terminals A and B is 20 V and Zener breakdown v...

    Text Solution

    |

  20. The logic gate realised from the circuit as shown in the figure is (A ...

    Text Solution

    |