Friction coefficient between block and inclined plane is `[mu=1/sqrt(3)]` if lift is moving vertically down with constant acceleration a then the value of acceleration a so that block moves down with constant velocity is

A block of mass is kept on an inclined plane of a lift moving down with acceleration of 2 ms^(-2) What should be the minimum coefficient of friction to let the block move down with constant velocity?

A block placed on an inclined plane making an angle 17^(@) with the horizontal slides down without any acceleration. What is the acceleration of the block if the inclimation is increased to 30^(@) ?

A block of mass 2 kg rests on an inclined plane which makes an angle of 30^(@) with the horizontal. The coefficient of friction between the block and the surface is sqrt(3//2) . (i) What force should be applied on the block so that it moves down without any acceleration ? (ii) What force should be applied on the block so that it moves up without any acceleration ? (iii) Calculate the ratio of the powers in the above two cases if the block moves with uniform speed in both the cases.

In the given figure the co- efficient of friction between the block and the incline plane is '1'. The acceleration with which the system should be accelerated so that the friction between the block and the wedge becomes zero ( g = 10 m//s^(2) ) is

A block is placed on a smooth inclined plane at an angle 'theta' to the horizontal. The acceleration must the plane be moved horizontally so that the block to fall freely is

A block slides down on inclined plane (angle of inclination 60^(@) ) with an accelration g//2 Find the coefficient friction

A block of mass m is lying on a wedge having inclination angle alpha = tan^(-1)((1)/(5)) wedge is moving with a constant acceleration a = 2 ms^(-2) The minimum value of coefficient of friction mu so that m remain stationary w.r.t. wedge is

An inclined plane of angule a is fixed onto a horizontal turntable with its line of greater slope in same plane as a diameter of forntable .A small block is placed on the inclined plane a distance r from the axis the coefficient of fraction between the block and the inclined plane is mu The turntable along with incline plane spins about its axis with constant minimum angular velocity omega a. Find an capression for the minimum angular velocity omega to prevent the block from sliding down the plane in term of g, r, mu and the plane omega b. Now a block of mass but having coefficient friction (with inclined plane) 2mu is kept instead of the original block . find the radius of friction force acting between block and incline now to the friction force active in part (a)

The coefficient of static friction between a block of mass m and an incline is mu_s=0.3 , a. What can be the maximum angle theta of the incline with the horizontal so that the block does not slip on the plane? b. If the incline makes an angle theta/2 with the horizontal, find the frictional force on the block.