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The radius of gyration of a uniform squa...

The radius of gyration of a uniform square plate of mass M and sida about its diagonal is

A

`a/sqrt(6)`

B

`a/sqrt(12)`

C

`a/2 sqrt(2)`

D

`a/4`

Text Solution

AI Generated Solution

The correct Answer is:
To find the radius of gyration of a uniform square plate of mass \( M \) and side \( A \) about its diagonal, we can follow these steps: ### Step 1: Understand the Moment of Inertia The moment of inertia \( I \) of a body about an axis is related to its mass and the radius of gyration \( k \) by the formula: \[ I = M k^2 \] We need to find the moment of inertia of the square plate about its diagonal. ### Step 2: Use the Perpendicular Axis Theorem For a flat plate, the perpendicular axis theorem states that: \[ I_z = I_x + I_y \] where \( I_z \) is the moment of inertia about an axis perpendicular to the plane of the plate, and \( I_x \) and \( I_y \) are the moments of inertia about two perpendicular axes in the plane of the plate. ### Step 3: Calculate the Moment of Inertia for the Square Plate For a square plate of side \( A \): - The moment of inertia about an axis through the center and parallel to one side (let's say \( I_x \)) is given by: \[ I_x = \frac{M A^2}{12} \] - Due to symmetry, the moment of inertia about the other axis \( I_y \) is the same: \[ I_y = \frac{M A^2}{12} \] ### Step 4: Apply the Perpendicular Axis Theorem Now, applying the perpendicular axis theorem: \[ I_z = I_x + I_y = \frac{M A^2}{12} + \frac{M A^2}{12} = \frac{M A^2}{6} \] ### Step 5: Find the Moment of Inertia About the Diagonal Since the square plate is symmetric, the moment of inertia about either diagonal (let's call it \( I_d \)) will be: \[ I_d = \frac{I_z}{2} = \frac{M A^2}{12} \] ### Step 6: Relate Moment of Inertia to Radius of Gyration Now, using the relation \( I = M k^2 \): \[ \frac{M A^2}{12} = M k^2 \] Dividing both sides by \( M \): \[ k^2 = \frac{A^2}{12} \] Taking the square root: \[ k = \frac{A}{2\sqrt{3}} \] ### Step 7: Rationalize the Result To rationalize \( k \): \[ k = \frac{A \sqrt{3}}{6} \] ### Final Answer Thus, the radius of gyration of the uniform square plate about its diagonal is: \[ k = \frac{A \sqrt{3}}{6} \] ---
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