Home
Class 12
PHYSICS
Two bodies of mass 2 kg and 5 kg have po...

Two bodies of mass 2 kg and 5 kg have position (1 m, 2 m, 1 m) and (3 m, 2 m, -1 m) respectively. The position vector of centre of mass is

A

`(17/7""hat I +2hatj-3/7""hatk)m`

B

`(17hati+2hatj-3/7hatk)m`

C

`(2hati+17/7""hatj-3/7""hatk)m`

D

`(14hati+17hatj-3hatk)m`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

Two bodies of masses m_1 and m_2(

Two bodies of masses 1kg and 3kg are lying in xy plane at (0,0) and (2,-1) respectively. What are the coordinates of the centre of mass ? Hint. x_(cm)=(m_(1)x_(1)+m_(2)x_(2))/(m_(1)+x_(2)) , y_(cm)=(m_(1)y_(1)+m_(2)y_(2))/(m_(1)+m_(2))

Two particles of masses 2 kg and 4 kg are placed along x-axis at positions x = 1 m and x = 4 m respectively. The moment of inertia of the system about an axis passing through centre of mass and parallel to y-axis is

Two particles of masses 1 kg and 3 kg have position vectors 2hati+3hatj+4hatk and-2hati+3hatj-4hatk respectively. The centre of mass has a position vector

Two particles of masses 1 kg and 3 kg have position vectors 2hati+3hatj+4hatk and-2hati+3hatj-4hatk respectively. The centre of mass has a position vector

Four particles, each of mass 1kg, are placed at the corners of a square OABC of side 1m. 'O' is at the origin of the coordinate system. OA and OC are aligned along positive x-axis and positive y-axis respectively. The position vector of the centre of mass is (in 'm')

Three bodies having masses 5 kg, 4 kg and 2 kg is moving at the speed of 5 m//s and 2 m//s and 5 m/s respectively along X-axis.The magnitude of velocity of centre of mass is

Three particles of masses m , m and 4kg are kept at a verticals of triangle ABC . Coordinates of A , B and C are (1,2) , (3,2) and (-2,-2) respectively such that the centre of mass lies at origin. Find the value of mass m . Hint. x_(cm)=(sum_(i-1)^(3)m_(i)x_(i))/(sum_(i=1)^(3)m_(i)) , y_(cm)=(sum_(i=1)^(3)m_(i)y_(i))/(sum_(i=1)^(3)m_(i))

Three particles of masses m , m and 4kg are kept at a verticals of triangle ABC . Coordinates of A , B and C are (1,2) , (3,2) and (-2,-2) respectively such that the centre of mass lies at origin. Find the value of mass m . Hint. x_(cm)=(sum_(i-1)^(3)m_(i)x_(i))/(sum_(i=1)^(3)m_(i)) , y_(cm)=(sum_(i=1)^(3)m_(i)y_(i))/(sum_(i=1)^(3)m_(i))

Two particles of mass 1 kg and 0.5 kg are moving in the same direction with speed of 2 m//s and 6 m/s respectively on a smooth horizontal surface. The speed of centre of mass of the system is