Home
Class 12
PHYSICS
The excess pressure inside a soap bubble...

The excess pressure inside a soap bubble is equal to an oil column of height `3` mm. The total surface area of the Soap bubble in contact with air will be ( given density of oil= 0.9`gm/cm^3`, surface tension of soap solution= `0.03` N/m and g= `10` `ms^(-2)) `

A

`4.96×10^(-4) m^2`

B

`2.43×10^(-4) m^2`

C

`3.72×10^(-4) m^2`

D

`1.03×10^(-4) m^2`

Text Solution

AI Generated Solution

Promotional Banner

Similar Questions

Explore conceptually related problems

If the excess pressure inside a soap bubble is balanced by an oil column of height 2 cm, then the surface tension of soap solution will be(r=1cm , density of oil =0.8g/cm 3 )

The excess pressure inside a soap bubble of radius R is (S is the surface tension)

The excess pressure inside one soap bubble is three times that inside a second soap bubble, then the ratio of their surface area is:

The excess pressure inside a soap bubble of radius 6mm is balanced by 2mm column of all of density 800 kgm^(-3) . Find the surface tension of soap solution.

The pressure inside a soap bubble of radius 1 cm balances a 1.5 mm column of oil of density 800 kg m^(-3) . Find the surface tension of the soap solution.

Work done in increasing the size of a soap bubble from a radius of 3 cm to 5 cm is nearly. (surface tension of soap solution = 0.3 Nm^(-1))

Work done in increasing the size of a soap bubble from a radius of 3cm to 5cm is nearly (Surface tension of soap solution =0.03Nm^-1 )

A soap film in formed on a frame of area 4xx10^(-3)m^(2) . If the area of the film in reduced to half, then the change in the potential energy of the film is (surface tension of soap solution =40xx10^(-3)N//m)

A 0.02 cm liquid column balances the excess pressure inside a soap bubble of radius 7.5 mm. Determine the density of the liquid. Surface tension of soap solution 0.03 Nm^-1 .

0.04 cm liquid column balances the excess pressure inside a soap bubble of radius 6 mm. Evaluate density of the liquid. Surface tension of soap solurtion = 0.03 Nm^(-1) .