Home
Class 12
PHYSICS
A parallel plate capacitor with liquid f...

A parallel plate capacitor with liquid filled between the plates (dielectric constant of liquid, `k= 4`)has capacitance `20 muF`. If the liquid is removed then capacitance of capacitor becomes

A

`10mu F`

B

`5mu F`

C

`80muF`

D

`20muF`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

A parallel plate condenser with oil (dielectric constant 2) between the plates has capacitance C. If oil is removed, the capacitance of capacitor becomes

The capacitor shown has square plates of side L and has gap d between the photos. In the dielectric constant of the materiale of the slab is k , the capacitance of the capacitor is

The two plates of a parallel plate capacitor are 4 mm apart. A slab of dielectric constant 3 and thickness 3 mm is introduced between the plates is so adjusted that the capacitance of the capacitor becomes (2)/(3) rd of its original value. What is the new distance between the plates ?

You are given an air filled parallel plate capacitor c_(1) . The space between its plates is now filled with slabs of dielectric constant k_(1) and k_(2) as shown in c_(2) . Find the capacitances of the capacitor c_(2) if area of the plates is A distance between the plates is d.

To reduce the capacitance of parallel plate capacitor, the space between the plate is

A parallel plate capacitor with air between the plates has a capacitance of 10 pF. The capacitance, if the distance bgetween the plates is reduced by half and the space between tehm is filled with a substance of dielectric constant 4 is

A parallel plate capacitor, with plate area A and plate separation d, is filled with a dielectric slabe as shown. What is the capacitance of the arrangement ?

In a parallel-plate capacitor, the region between the plates is filled by a dielectric slab. The capacitor is connected to a cell and the slab is taken out. Then

A parallel plate air capacitor has a capacitance C. When it is half filled with a dielectric of dielectric constant 5, the percentage increase in the capacitance will be

A parallel plate capacitor with air between the plates has a capacitance of 8 pF. (1 pF = 10^(-12)F) What will be the capacitance if the distance between the plates is reduced by half and the space between them is filled with a substance of dielectric constant 6 ?