When a force vecF = (6hati - 2hatj) N di...

When a force `vecF = (6hati - 2hatj)` N displaces a particle by `vecS = (2hati - 3hatj)` m, then average power is `0.4 w`. The time of action of force is

A

`10 s`

B

`20 s`

C

`45 s`

D

`40 s`

AI Generated Solution

Similar Questions

Explore conceptually related problems

A force F=(2hati-hatj+4hatk)N displaces a particle upto d=(3hati+2hatj+hat k)m. Work done by the force is

A force (3hati+2hatj) N displaces an object through a distance (2hati-3hatj) m. The work done is :

A force F = 2hati + 4hatj Newton displaces the body by s = 3hatj + 5hatk meter in 2s. The power generated will be

A force vecF= (3hati+4hatj) N acts on a body and displaces it by vecS= (3hati+4hatj)m . The work done (W= vecF*vecS ) by the force is :

A force vecF=6xhati+2yhatj displaces a body from vecr_1=3hati+8hatj to vecr_2=5hati-4hatj . Find the work done by the force.

The angle between force vecF =(3hati+4hatj-5hatk) unit and displacement vecd = (5hati+4hatj+3hatk) unit is

A force (3hati+4hatj) newton acts on a boby and displaces it by (2hati+3hatj) metre. The work done by the force is

A force (hati-2hatj+3hatk) acts on a particle of position vector (3hati+2hatj+hatk) . Calculate the torque acting on the particle.

Find the torque of a force vecF= -3hati+hatj+5hatk acting at the point vecr=7hati+3hatj+hatk