10 g of ice at 0 C is slowly melted to water at 0 C. The latent heat of melting is 80 cal /g. the change in entropy is ?(cal/k)

1 kg of ice at 0^(@)C is mixed with 1.5 kg of water at 45^(@)C [latent heat of fusion = 80 cal//gl. Then

120 g of ice at 0^(@)C is mixed with 100 g of water at 80^(@)C . Latent heat of fusion is 80 cal/g and specific heat of water is 1 cal/ g-.^(@)C . The final temperature of the mixture is

The amount of heat required to raise the temperature of 75 kg of ice at 0^oC to water at 10^oC is (latent heat of fusion of ice is 80 cal/g, specific heat of water is 1 cal/ g^oC )

A metal rod AB of length 10x has it one end in ice at 0^(@)C and the other end B in water at 100^(@)C If a point P on the rod is maintained at 400^(@)C then it is found that equal amounts of water and ice evaporate and melt per unit time. The latent heat of melting of ice is 80cal//g If the point P is at a distance of lambdax from the ice end A find the value of lambda [neglect any heat loss to the surrounding] . .

50 g of ice at 0^@C is mixed with 50 g of water at 80^@C . The final temperature of the mixture is (latent heat of fusion of ice =80 cal //g , s_(w) = 1 cal //g ^@C)

What will be the final temperature when 150 g of ice at 0^@C is mixed with 300 g of water at 50^@C . Specific heat of water =1 cal//g//^@C . Latent heat of fusion of ice =80 cal//g .

When 1 kg of ice at 0^(@)C melts to water at 0^(@)C , the resulting change in its entropy, taking latent heat of ice to be 80 cal//g is

An iron ball of mass 0.2 kg is heated to 10^(@)C and put into a block of ice at 0^(@)C . 25 g of ice melts. If the latent heat of fusion of ice is 80 cal g^(-1) , then the specific heat of iron in cal g^(-1^(@))C is

1 g ice at 0^@ C melts to form 1 g water at 0^@ C. State whether the latent heat is absorbed or given out by ice.

When 1 g of ice at 0^(@)C melts to form 1 g of water at 0^(@)C then, is the latent heat absorbed by the ice or given out by it?