The circuit shown in figure contains two diodes each with a forward resistance of `50Ω` and infinite reverse resistance.If the battery voltage is 6 v ,then the current through the `100Ω` resistance is

Options

A. 0.04A
B. 0.02A
C. 0.2A
D. 0.15A

Answer

To solve the problem, we need to analyze the circuit with the two diodes and the resistors. Here’s a step-by-step solution:

### Step 1: Identify the configuration of the diodes
- The circuit contains two diodes, D1 and D2.
- D1 is connected in forward bias because the positive terminal of the battery is connected to the anode of D1.
- D2 is connected in reverse bias because the positive terminal of the battery is connected to the cathode of D2.

**Hint:** Check the orientation of the diodes with respect to the battery to determine if they are in forward or reverse bias.

### Step 2: Determine the effective resistance in the circuit
- Since D1 is forward biased, it has a forward resistance of 50Ω.
- D2, being reverse biased, behaves like an open circuit and does not contribute to the current.
- The total resistance in the circuit consists of the forward resistance of D1 (50Ω) and the 100Ω resistor in series.

**Hint:** Remember that in a series circuit, you can simply add the resistances.

### Step 3: Calculate the total resistance
- The total resistance (R_total) in the circuit is:
\[ R_{\text{total}} = R_{D1} + R_{100} = 50Ω + 100Ω = 150Ω \]

**Hint:** Ensure you only include resistances that are in the path of the current.

### Step 4: Apply Ohm's Law to find the current
- According to Ohm's Law, the current (I) can be calculated using the formula:
\[ I = \frac{V}{R} \]
- Here, V = 6V (the battery voltage) and R = 150Ω (the total resistance calculated in the previous step).

**Hint:** Make sure to use the correct values for voltage and resistance in the formula.

### Step 5: Calculate the current
- Plugging in the values:
\[ I = \frac{6V}{150Ω} = 0.04A \]

**Hint:** Double-check your arithmetic to ensure accuracy in the calculation.

### Step 6: Determine the current through the 100Ω resistor
- Since the current in a series circuit is the same through all components, the current through the 100Ω resistor (I100) is also 0.04A.

**Hint:** Remember that in a series circuit, the current remains constant throughout all components.

### Final Answer
The current through the 100Ω resistance is **0.04 A**.

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