DNA content in a meiocyte at `G_2` phase is 40 pg. What would be the DNA content after meiosis-II in the daughter cells?

Options

A. 20 pg
B. 5 pg
C. 10 pg
D. 15 pg

Answer

To solve the question regarding the DNA content in a meiocyte at the G2 phase and its subsequent content after meiosis II, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the G2 Phase:**
- The G2 phase is part of the cell cycle where the cell prepares for division. At this phase, the DNA content is at its maximum because DNA replication has occurred during the S phase.
- Given that the DNA content in the meiocyte at G2 is 40 picograms (pg), this is the total amount of DNA present in the cell before meiosis begins.

2. **Meiosis Overview:**
- Meiosis consists of two rounds of division: Meiosis I and Meiosis II.
- Meiosis I reduces the chromosome number by half, but the DNA content remains the same until the end of Meiosis II.

3. **DNA Content After Meiosis I:**
- After Meiosis I, the cell divides into two daughter cells. However, the DNA content in each daughter cell remains the same as the original meiocyte at G2, which is still 40 pg.
- This is because Meiosis I separates homologous chromosomes but does not reduce the DNA content yet.

4. **DNA Content After Meiosis II:**
- In Meiosis II, the two daughter cells from Meiosis I divide again. This division separates sister chromatids, effectively halving the DNA content in each daughter cell.
- Therefore, after Meiosis II, the DNA content in each of the four daughter cells will be half of the DNA content present after Meiosis I.

5. **Calculating the Final DNA Content:**
- Since the DNA content after Meiosis I is 40 pg, after Meiosis II, the DNA content in each daughter cell will be:
\[ \text{DNA content after Meiosis II} = \frac{40 \text{ pg}}{2} = 20 \text{ pg} \]

### Final Answer:
The DNA content in each daughter cell after Meiosis II will be **20 picograms (pg)**.

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