For heterozygous tall plant of pea undergoing selfing, what would be the sum of phenotype and genotypes obtained in F1 generation?

Options

A. 2
B. 5
C. 3
D. 4

Answer

To solve the question regarding the sum of phenotypes and genotypes obtained in the F1 generation from a heterozygous tall pea plant undergoing selfing, we can follow these steps:

### Step 1: Understand the Genotype of the Parent Plant
The parent plant is heterozygous for the tall trait, which means its genotype is Tt (where T = tall and t = dwarf).

### Step 2: Perform the Selfing Cross
When we perform selfing (Tt x Tt), we can set up a Punnett square to determine the possible genotypes of the offspring.

### Step 3: Fill in the Punnett Square
The Punnett square for Tt x Tt is as follows:

| | T | t |
|---|---|---|
| T | TT | Tt |
| t | Tt | tt |

### Step 4: Determine the Genotypes
From the Punnett square, we can identify the genotypes of the F1 generation:
- TT (homozygous tall)
- Tt (heterozygous tall)
- tt (homozygous dwarf)

### Step 5: Count the Genotypes
The genotypes obtained are:
1. TT
2. Tt
3. tt

Thus, there are a total of 3 different genotypes.

### Step 6: Determine the Phenotypes
Next, we identify the phenotypes:
- Tall (TT and Tt)
- Dwarf (tt)

Thus, there are 2 different phenotypes.

### Step 7: Sum of Phenotypes and Genotypes
Now we sum the number of different phenotypes and genotypes:
- Number of genotypes = 3
- Number of phenotypes = 2

Sum = 3 (genotypes) + 2 (phenotypes) = 5

### Final Answer
The sum of the phenotypes and genotypes obtained in the F1 generation is **5**.

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