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A circle of constant radius a passes th...

A circle of constant radius `a` passes through the origin `O` and cuts the axes of coordinates at points `P` and `Q` . Then the equation of the locus of the foot of perpendicular from `O` to `P Q` is `(x^2+y^2)(1/(x^2)+1/(y^2))=4a^2` `(x^2+y^2)^2(1/(x^2)+1/(y^2))=a^2` `(x^2+y^2)^2(1/(x^2)+1/(y^2))=4a^2` `(x^2+y^2)(1/(x^2)+1/(y^2))=a^2`

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A circle of constant radius a passes through the origin O and cuts the axes of coordinates at points P and Q . Then the equation of the locus of the foot of perpendicular from O to P Q is (A) (x^2+y^2)(1/(x^2)+1/(y^2))=4a^2 (B) (x^2+y^2)^2(1/(x^2)+1/(y^2))=a^2 (C) (x^2+y^2)^2(1/(x^2)+1/(y^2))=4a^2 (D) (x^2+y^2)(1/(x^2)+1/(y^2))=a^2

A circle of constant radius a passes through the origin O and cuts the axes of coordinates at points P and Q . Then the equation of the locus of the foot of perpendicular from O to P Q is (A) (x^2+y^2)(1/(x^2)+1/(y^2))=4a^2 (B) (x^2+y^2)^2(1/(x^2)+1/(y^2))=a^2 (C) (x^2+y^2)^2(1/(x^2)+1/(y^2))=4a^2 (D) (x^2+y^2)(1/(x^2)+1/(y^2))=a^2

A circle of constant radius a passes through the origin O and cuts the axes of coordinates at points P and Q . Then the equation of the locus of the foot of perpendicular from O to P Q is (A) (x^2+y^2)(1/(x^2)+1/(y^2))=4a^2 (B) (x^2+y^2)^2(1/(x^2)+1/(y^2))=a^2 (C) (x^2+y^2)^2(1/(x^2)+1/(y^2))=4a^2 (D) (x^2+y^2)(1/(x^2)+1/(y^2))=a^2

A circle of radius r passes through origin and cut the x-axis and y-axis at P and Q . The locus of foot of perpendicular drawn from origin upon line joining the points P and Q is (A) (x^2+y^2)^3=r^2(x^2y^2) (B) (x^2+y^2)^2(x+y)=r^2(xy) (C) (x^2+y^2)^2=r^2(x^2y^2) (D) (x^2+y^2)^3=4r^2(x^2y^2)

A circle of radius r passes through origin and cut the y-axis at P and Q. The locus of foot of perpendicular drawn from origin upon line joining the points P and Q is (A) (x^(2)+y^(2))^(3)=r^(2)(x^(2)y^(2))(B)(x^(2)+y^(2))^(2)(x+y)=r^(2)(xy)(C)(x^(2)+y^(2))^(2)=r^(2)(x^(2)y^(2))(D)(x^(2)+y^(2))^(3)=4r^(2)(x^(2)y^(2))

The locus of the foot of the perpendicular from the center of the hyperbola x y=1 on a variable tangent is (x^2+y^2)^2=4x y (b) (x^2-y^2)=1/9 (x^2-y^2)=7/(144) (d) (x^2-y^2)=1/(16)

The locus of the foot of the perpendicular from the center of the hyperbola x y=1 on a variable tangent is (x^2-y^2)=4x y (b) (x^2-y^2)=1/9 (x^2-y^2)=7/(144) (d) (x^2-y^2)=1/(16)

The locus of the foot of the perpendicular from the center of the hyperbola x y=1 on a variable tangent is (a) (x^2+y^2)^2=4x y (b) (x^2-y^2)=1/9 (x^2-y^2)=7/(144) (d) (x^2-y^2)=1/(16)

The locus of the foot of the perpendicular from the center of the hyperbola x y=1 on a variable tangent is (a) (x^(2)+y^(2))^(2)=4xy (b) (x^2-y^2)=1/9 (c) (x^2-y^2)=7/(144) (d) (x^2-y^2)=1/(16)

The equation of the curve passing through origin, whose slope at any point is (x(1+y))/(1+x^2) , is (A) (1+y)^2-x^2=1 (B) x^2+(y+1)^2=1 (C) (x+y)y=1-x^2 (D) x=ye^((1+y))