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If the frequency of occurrence of domina...

If the frequency of occurrence of dominant allele A is p and that of recessive allele a is q. Then according to Hardy Weinberg law q is equal to.

A

`1+p`

B

`1-p^2-2pq`

C

`1-p`

D

Both (1) and (2)

Text Solution

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The correct Answer is:
To solve the question regarding the Hardy-Weinberg law and the relationship between the frequencies of dominant and recessive alleles, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Allele Frequencies**: - Let the frequency of the dominant allele \( A \) be represented as \( p \). - Let the frequency of the recessive allele \( a \) be represented as \( q \). 2. **Hardy-Weinberg Principle**: - According to the Hardy-Weinberg principle, the sum of the frequencies of all alleles in a population must equal 1. This can be expressed as: \[ p + q = 1 \] 3. **Rearranging the Equation**: - To find \( q \), we can rearrange the equation: \[ q = 1 - p \] 4. **Conclusion**: - Therefore, according to the Hardy-Weinberg law, the frequency of the recessive allele \( q \) is equal to \( 1 - p \). ### Final Answer: Thus, the answer to the question is: \[ q = 1 - p \]
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