If `p=tan20^@` express `(tan160^@-tan110^@)/(1+tan160^@.tan110^@)` in terms of p.

If cot 20^@=p then (tan16 0^(@)-tan11 0^(@))/(1+tan16 0^(@)tan11 0^(@))=

tan20^(@)tan40^(@)tan60^(@)tan80^(@)

tan20^(@)tan40^(@)tan60^(@)tan80^(@)=?

If tan20=lambda ,prove that (tan160^(@)-tan110^(@))/(1+tan160^(@)*tan110^(@))=(1-lambda^(2))/(2 lambda) .

If tan 20^(@) =lamda, then (tan 160^(@) -tan 110^(@))/(1+ (tan 160^(@)) (tan 110^(@)))=

tan20^(@)tan30^(@)tan40^(@)tan80^(@)=1

tan20^(@)tan40^(@)tan80^(@)

If : p = cot 20^(@),"then": (tan 160^(@) - tan 110^(@))/(1 +tan 160^(@) * tan 110^(@))= A) (p^(2)-1)/(2p) B) (p^(2)+1)/(2p) C) (1-p^(2))/(2p) D) (2p)/(1 + p^(2))