The linear charge density on a dielectric ring of radius `R` vanes with `theta` as `lambda = lambda_0 cos theta//2`, where `lambda_0` is constant. Find the potential at the center `O` of the ring [in volt].

The linear charge density on a ring of radius R is lambda=lambda_0 sin (theta) where lambda_0 is a constant and theta is angle of radius vector of any point on the ring with x-axis. The electric potential at centre of ring is

A semicircular wire is uniformly charged with linear charge density dependent on the angle theta from y -direction as lambda=lambda_(0) |sin theta| , where lambda_(0) is a constant. The electric field intensity at the centre of the arc is

The linear charge density of a uniform semicircular wire varies with theta shown in the figure as lambda=lambda_(0)costheta if R is the radius of the loop ,of the charge on the wire is

A thin nonconducting ring of radius R has a linear charge density lambda = lambda_(0) cos varphi , where lambda_(0) is a constant , phi is the azimutahl angle. Find the magnitude of the electric field strength (a) at the centre of the ring , (b) on the axis of the ring as a function of the distance x from its centre. Investegation the obtained function at x gt gt R .

the linear charge density of a thin metallic rod varies with the distance x from the end as lambda=lambda_(0)x^(2)(0 le x lel) The total charge on the rod is

A thin non-conducting ring of radius R has a linear charge density lambda=lambda_(0) cos theta , where theta is measured as shown. The total electric dipole moment of the charge distribution is

A half ring of radius r has a linear charge density lambda .The potential at the centre of the half ring is

A rod with linear charge density lambda is bent in the shap of circular ring. The electric potential at the centre of the circular ring is

If linear charge density of a wire of length L depends on distance x from one end as lambda=(lambda_(0)(x))/(L .Find total charge of wire :-