A small block slides without friction down an iclined plane starting form rest. Let `S_(n)` be the distance traveled from time `t = n - 1` to `t = n`. Then `(S_(n))/(S_(n + 1))` is:

A particle starts sliding down a frictionless inclined plane. If S_(n) is the distance travelled by it from time t = n-1 sec , to t = n sec , the ratio (S_(n))/(s_(n+1)) is

If S_(n) denotes the sum of first n terms of an A.P., then (S_(3n)-S_(n-1))/(S_(2n)-S_(n-1)) is equal to

t_ (n) = 3-4n, find S_ (20)

In an A.P. if a=2, t_(n)=34 ,S_(n) =90 , then n=

If S=t^(n) , where n ne 0 , then velocity equal acceleration at time t=3 sec if : n=

(1) .Let S_n denote the sum of the first 'n' terms and S_(2n)= 3S_n. Then, the ratio S_(3n):S_n is: (2) let S_1(n) be the sum of the first n terms arithmetic progression 8, 12, 16,..... and S_2(n) be the sum of the first n terms of arithmatic progression 17, 19, 21,....... if S_1(n)=S_2(n) then this common sum is

Let S_(n) be the sum of n terms of an A.P. Let us define a_(n)=(S_(3n))/(S_(2n)-S_(n)) then sum_(r=1)^(oo)(a_(r))/(2^(r-1)) is