The potential energy U for a force field `vec (F)` is such that `U=-`kxy where K is a constant . Then

The potential energy of a force filed vec(F) is given by U(x,y)=sin(x+y) . The force acting on the particle of mass m at (0,(pi)/4) is

The potential energy of configuration changes in x and y directions as U=kxy , where k is a positive constant. Find the force acting on the particle of the system as the function of x and y.

The potential energy of a conservative force field is given by U=ax^(2)-bx where, a and b are positive constants. Find the equilibrium position and discuss whether the equilibrium is stable, unstable or neutral.

The potential energy for a conservative force system is given by U=ax^(2)-bx . Where a and b are constants find out (a) The expression of force (b) Potential energy at equilibrium.

The potential energy function of a particle in the x-y plane is given by U =k(x+y) , where (k) is a constant. The work done by the conservative force in moving a particlae from (1,1) to (2,3) is .

The potential energy of a body is given by U = A - Bx^(2) (where x is the displacement). The magnitude of force acting on the partical is