In young's double slit experiment the ratio of maximum and minimum intensity in the interference experiment is `9:1` .Then The ratio of the amplitudes of coherent sources is :

In Young's double slit experiment, the ratio of maximum and minimum intensities in the fringe system is 9:1 the ratio of amplitudes of coherent sources is

If ratio of maximum to minimum intensity in an interference experiment is 16:1 then ratio of amplitudes of individual waves is-

In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is 4 : 1 . The amplitudes of the coherent sources are in the ratio

In Young's double slit experiment, if one of the slit is closed fully, then in the interference pattern

In a Young's double slit interference experiment, the ratio of intensity at the maxima and minima in the interference pattern is 25/9 . What will be the ratio of amplitudes of light emitted by the two slits?

In Young's experiment the ratio of intensity at the maxima and minima in the interference patner is 3:16 . What is the ratio of the widths of the two slits

Youngs Double slit experiment | variation of intensity on screen

In Young's double slit experiment, the widths of two slits are n the ratio 4 : 1 . The ratio of maximum and minimum intensity in the interference pattern will be :

In Young's double slit experiment the ratio of intensities at the position of maxima and minima is 9/1. the ratio of amplitudes of light waves is

Two waves have their amplitudes in the ratio 1 : 9 . The maximum and minimum intensities when they interfere are in the ratio