At a certain height a shell at rest explodes into two equal fragments one of the fragments receives a horizontal velocity `u`.The time interval after which the velocity vectors will be inclined at `120^(@)` to each other is

At a certain height a body at rest explodes into two equal fragments with one fragment receiving a horizontal velocity of 10ms^(-1) The time interval after the explosion for which the velocity vectors of the two fragments become perpendicular to each other is (g=10ms^(-2))

A bomb is rest at the summit of a cliff breaks into two equal fragments.One of the fragments attains a horizontal velocity of 20sqrt3 ms^(-1) .The horizontal distance between the two fragments, when their displacement vectors is inclined at 60^(@) relative to each other is (g=10ms^(-2))

A bomb explodes in air in two equal fragments. If one of the fragments is moving vertically upwards with velocity v_(0) , then the other fragment is moving-

At high altitude , a body explodes at rest into two equal fragments with one fragment receiving horizontal velocity of 10 m//s . Time taken by the two radius vectors connecting of explosion to fragments to make 90^(@) is

A particle of mass 4m which is at rest explodes into four equal fragments. All 4 fragments are scattered in the same horizontal plane. Three fragments are found to move with velocity V each as shown in the figure. The total energy released in the process of explosion is

A particle of mass 4m which is at rest explodes into four equal fragments. All four fragments scattered in the same horizontal plane. Three fragments are found to move with velocity v as shown in the figure. The total energy released in the process is

A ball is projected with a velocity 20 sqrt(3) ms^(-1) at angle 60^(@) to the horizontal. The time interval after which the velocity vector will make an angle 30^(@) to the horizontal is (Take, g = 10 ms^(-2))