`f(a) = log((1-a)/(1+a))` for `0`< `a` <`1` then `f((2a)/(1+a))`

If f(a) = log"" (1 + a)/(1-a) then f((2a)/(1+a^(2))) is equal to

If f.(x)= log((1+x)/(1-x)) , then

If f(x) is continuous at x=0 , where f(x)={:{(log_((1-2x))(1+2x)", for " x!=0),(k", for " x=0):} , then k=

If the f(x) =(log(1+ax)-log(1-bx))/x , xne0 is continuous at x = 0 then, f(0) = .....

Value of f(0) so that f(x) = (log(1+bx)-log(1-ax))/x is continuous at x = 0 is

The function f(x) = (log(1+ax)-log(1-bx))/x is not difined at x = 0. The value which should be assigned to f at x = 0, so that it is continuous at x = 0, is