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The mass of an electron is 9.1xx10^(-31)...

The mass of an electron is `9.1xx10^(-31)kg` . If its K.E . Is `3.0xx10^(-25)J` , calculate its wavelength .

Text Solution

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Since K.E. `=1//2mv^(2)`
`v=((2K.E)/(m))^(1//2)`
`=((2xx3.0xx10^(-25)kgm^(2)s^(-2))/(9.1xx10^(-31kg)))^(1//2)`
`=812ms^(-1)`
`lamda=(h)/(mv)=(6.626xx10^(-34)Js)/((9.1xx10^(-31)kg)(812ms^(-1)))`
`=8967xx10^(10)m=896.7nm`
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