An atom of an element contains 29 electrons ans 35 neutrons . Deduce (i) the number of protons and (ii) the electromic configuration of the element .

Explanation

Given no:of electrons `29., `:.Z=299`
(i) So, no.of protons = 29
ii) Electronic configuration of the element (Z =29)
`=1s^(2)2s^(2)2p^(2)3s^(2)3p^(6)4s^(1)3d^(10)` (anamalous electronic.configuration)