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If the velocity of the electron is 1.6xx...

If the velocity of the electron is `1.6xx10^(6) "ms"^(-1)` , calculate the de-Broglie wavelength associated with this electron .

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Formulae :
`lamda=(h)/(mv)`
`=(6.625xx10^(-34))/(9.1xx10^(-31)xx1.6xx10^(6))`
`=0.455xx10^(-9)m`
=0.455 m.
`v=1.6xx10^(6)m//sec`
`h=6.625xx10^(-34)J.sec`
`m=9.1xx10^(-31)kg`.
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