Pressure of 1g of an ideal gas A at `27^@C` is found to be 2 bar. When 2g of another ideal gas B is introduced in the same flask at same temperature the pressure becomes 3 bar. Find the relationship between their molecular masses.

Explanation

Given :
Weight of gas A = 1 gm
Weight of gas B = 2 gms
Molecular mass of `A = M_A`
Molecular mass of `B = M_B`
Pressure of `A = P_A =-2` bar
Given Total pressure = 3 bar `(P_A + P_B)`
` therefore P_B = 3-2 =1 ` bar