`PCl_(5),PCl_(3)` and `Cl_(2)` are at equilibrium at `500K` and having concentration `1.59M PCl_(3), 1.59M CL_(2)` and `1.41 MPCl_(5)`. Calculate `K_(c)` for the reaction `PCl_(5)hArrPCl_(3)+Cl_(2)`

Explanation

The equilibrium constant `K_(c)` for the above reaction can be written as,
`K_(C)=([PCl_(3)][Cl_(2)])/([PCl_(5)])=((1.59)^(2))/((1.41))=1.79`