Calculate the solubility of `A_(2)X_(3)` is pure water, assuming that neither kind of ion racts with water. The solubility product of `A_(2)X_(3),K_(sp)=1.1xx10^(-23)`

Explanation

`A_(2)X_(3) hArr 2A^(3+)+3X^(2-)`
`K_(sp)=[A^(3+)].[X^(2-)]^(3)=1.1xx10^(-23)`
If S= solubiltiy of `A_(2)X_(3)` then ,br> `[A^(3+)]=2S, [X^(2)]=3S`
Therefore `K_(sp)=(2S)^(2)(3S)^(3)=108S^(5)`
`=1.1xx10^(-23)`
Thus `S^(5)=1xx10^(-25)`
`s=1.0xx10^(-5)` mol/L.