In an equilibrium `A+BhArrC+D,A` and B are mixed in a vessel at temperature T. The initial concentration of A was twice the initial concentration of B. After the attainment of equilibrium, concentration of C was thrice concentration of B, calculate `K_(c)`.

Explanation

Given
`A+B+hArr C+D`
The initial concentrations of A was twice the initial concentration of B and after the attaining of equilibrium concentration of .C. was thrice the concentration of .B..
`A+B hArr C+D`
Initial `2x" "x" "0" "0`
at equilibrium `(2x-a) (x-a) " " a" " a`
Given `3(x a)=a`
`:.x=(4a)/(3)`
`:.[A]=(2((4a)/(3))-a)`
`=(5a)/(3)`
`:. K_(C)=([C][D])/([A][B])=(a xxa)/((5a)/(3)xx(a)/(3))`
`=(9)/(5)=1.8`