A vessel at `100K` contains `CO_(2)` with a pressure of 0.5 atm. Some of the `CO_(2)` is converted into CO on addition of graphite. Calculate the value of K if total pressure at equilibrium is 0.8 atm.

Explanation

`CO_(2_((g)))+C_("grraphlte") hArr 2CO_(g)`
Initial `0.5 "atm" " " O`
at equilibrium `0.5-x " " 2x`
Total pressure at equilibrium
`0.5-x+22x=0.8`
`x=03`
`:. P_(CO)=0.2` atm ,br> `P_(CO_(2))=0.6 ` atm
`K=(P_(CO_(2)^(2)))/(P_(CO))`
`=(0.36)/(0.2)=1.8`