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0.5 mol of H(2) and 0.5 mole of I(2) re...

0.5 mol of `H_(2)` and 0.5 mole of `I_(2)` react in 10 litre flast at `448^(@)C`. The equilibrium constant `K_(c)` is 50 for
`H_(2)(g)+I_(2)(g)hArr2HI(g)`
a. What is the value of `K_(p)`
b. Calculate mole of `I_(2)` at equilibrium.

Text Solution

Verified by Experts

`H_(2_((g)))+I_(2_((g))) hArr 2HI_((g))`
Forthise reaction
`K_(P)=K_(C) " " :. Deltan=0`
`:. K_(P)=K_(C)=50`
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