How much `PCl_(5)` must be added to a one litre vesel at `250^(@)C` in order to obtain concentration of 0.1 mole of `Cl_(2)` at equilibrium `K_(C)` for `PCl_(5)(g) hArr PCl_(3(g)+Cl_(2)` is 0.0414M

Explanation

`PCl_(5_((g))) hArr PCl_(3_((g)))+Cl_(2_((g)))`
`{:("Initial", x,0,0),("At equilibrium",x-a,a,a):}`
Given `[Cl_(2)]=0.1` moles/lit
`K_(C)=0.0414`
`:. K_(C)=([PCl_(3)][Cl_(2)])/([PCl_(5)])`
`0.0414=(0.1xx0.1)/(x-0.041)`
`0.0414x-0.00414=0.01`
`0.0414x=0.01+0.00414`
`x=0.34154` moles