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Calculate the pH for a. 0.001 M NaOH ...

Calculate the pH for
a. `0.001 M NaOH`
b. `0.01 M Ca(OH)_(2)`
c. `0.0008M Ba(OH)_(2)`
d. `0.004 M NaOH`

Text Solution

Verified by Experts

`0.0008 M Ba(OH)_(2)`
`pOH=-log[OH^(-)]`
`=0.0016N`
`:. pOH =-log0.0016`
`=-log16xx10^(-4)`
`=-log16+4 log10`
`=-log2^(4)+4=2.796`
`=-4log2+4=2.796`
`pH+pOH=14`
`pH=14-2.796`
`pH=11.204`
`10^(-6)m HO_(3)`
`PH=-log[H^(+)]`
`=-log10^(-6)`
`=6 log 10`
=6
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