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The pH of a solution is 8.6. Calculate t...

The pH of a solution is 8.6. Calculate the `OH^(-)` ion concentration
`pH=8.6`
`pOH=5.4`
`-log[OH^(-)]=10^(-5.4)`
`[OH^(-)]=10^(-6)xx10^(0.6)=10^(-6)xx` anto log 0.6
`[OH^(-)]=3.98xx10^(-6)`

Text Solution

Verified by Experts

`pH=14-pH`
`=14-8.6`
`=5.4`
`:. pOH=-log[OH^(-)]`
`log[OH^(-)]=0.5(or) bar(6). 6000`
`[OH^(-)]`= anti log of `bar(6). 6000`
`=3.981xx10^(-6)`
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