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A solutioin of 0.005 MH(2)SO(4) is dilut...

A solutioin of 0.005 `MH_(2)SO_(4)` is diluted 100 times. Calculate the pH of diluted solution.

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`0.005 M H_(2) SO_(4)`
`[H^(+)]=0.005xx2`
`=0.01`
It is diluted to 100 times
`[H^(+)]=(0.01)/(100)0.0001`
`pH=log[H^(+)]`
`=-log0.0001`
`=-log 10^(-4)=4`
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