Calculate the `pH` of the following solution :
`(a) 2g` of `TlOH` dissolved in water to give `2` litre of solution.
`(b)` `0.3g` of `Ca(OH)_(2)` dissolved in water to give `500mL` of solution.
`(c)` `0.3g` of `NaOH` dissolved in water to give `200mL` of solution.
`(d)` `1mL` of `13.6M HCl` is diluted with water to give `1` litre of solution.

Explanation

`:. [H^(+)]=13.6`
Diluted with water to 1 litrew solution
`:. [H^(+)]=(13.6)/(1000)=0.0136`
`pH=-log[H^(+)]`
`=-log0.0136=1.87`