What will be the resultant pH when 200 ml of an aqueous solution of HCl having `pH=2` is mixed with 300 ml of a aqueous solution of NaOH having `pH=12`?

Explanation

`V_(A)=200 ml " " V_(B)=300 ml`
`N_(A)=10^(-2) " " N_(B)=10^(-2)`
`[ :. pH=2] " " [ :.pOH=2]`
`:.V_(B)N_(B) gt V_(A)N_(A)`
`:. N=(300xx10^(-2)-200xx10^(-2))/(300+200)`
`=(1)/(500)=0.002=[OH^(-)]`
`pOH=-log[OH^(-)]`
`=-log[0.002]`
`=-32xx10^(-3)`
`=-log2+3log10`
`=3-log2`
`22.699`
`:> pH=14-pOH`
`=14.2.699`
`=11.3010`