Calculate the pH of 0.01 M solution of `CH_(3)COOH.K_(a)` for `CH_(3)COOH` at `298K` is `1.8xx10^(-5)`

Explanation

`alpha^(2)=(K_(a))/(C)`
`=(1.8xx10^(-5))/(0.01)`
`=180xx10^(-5)`
`=18xx10^(-4)`
`alpha=4.1xx10^(-2)`
`:.[H_(3)O^(+)]=0.01xx4.1xx10^(-2)`
`=4.1xx10^(-4)`
`pH=-log[H_(3)O^(+)]`
`=-log(4.1xx10^(-4))=3.38`