Home
Class 11
CHEMISTRY
The solibility product of Ag cl is 1.6xx...

The solibility product of Ag cl is `1.6xx10^(-10) "mol"^(2)//L^(2)`. What is its solubility?

Text Solution

Verified by Experts

`K_(SP)=S^(2)`
`1.6xx10^(-10)=S^(2)`
`:. S= sqrt(10^(-10)xx1.6))=1.3xx10^(-5)` moles/litre.
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM AND ACIDS BASES

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise IMPORTANT QUESTIONS|64 Videos

  • CHEMICAL EQUILIBRIUM AND ACIDS BASES

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise VERY SHORT ANSWER QUESTIONS |40 Videos

  • CHEMICAL EQUILIBRIUM AND ACIDS BASES

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise LONG ANSWER QUESTIONS |31 Videos

  • ATOMIC STRUCTURE

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise LONG ANSWER QUESTIONS |15 Videos

  • CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise Long Answer Questions|24 Videos

Similar Questions

Explore conceptually related problems

The solubility product of Zr(OH)_(2) is 4.5xx10^(-17) "mol"^(3)L^(-3) . What is solubility?

The solubility product of a salt AB=10^(-10) "mol"^(2)L^(-2) . What is the solubility?

The solubility of Ag_(2)CrO_(4) is 1.3xx10^(-4) "mol"L^(-1) . What is the solubility product?

The solubility product of PbS at 25^@ C is 9 xx 10^(-28) . What is its solubility in pure water and in 2 xx 10^(-12) M Na_2 S solution ?

If the solubility product of MOH is 1xx10^(-10) mol^(2).dm^(-2) . Then the p^(H) of the its aqueous solution will be

If the solubility product of MOH is 1xx 10^(-10) mol^(2) dm ^(-2) Then the P^(H) of its aqueous solutions will be

VIKRAM PUBLICATION ( ANDHRA PUBLICATION)-CHEMICAL EQUILIBRIUM AND ACIDS BASES -PROBLEMS
  1. K(a) of 0.02M CH^(3)COOH is 1.8xx10^(-5) Calculate a. [H(3)O^(+)] b....

    Text Solution

    |

  2. K(a) of 0.02M CH^(3)COOH is 1.8xx10^(-5) Calculate a. [H(3)O^(+)] b....

    Text Solution

    |

  3. Calculate the pH of 0.01 M solution of CH(3)COOH.K(a) for CH(3)COOH a...

    Text Solution

    |

  4. The pH of 0.1 M solution of an organic acid is 4.0. Calculate the diss...

    Text Solution

    |

  5. The ionization constants of HF, H COOH and HCN at 298 K are 6.8x10^(-4...

    Text Solution

    |

  6. Find the concentration of hydroxide ion in a 0.25 M solution of trimet...

    Text Solution

    |

  7. The 0.005 M monobasic acid has a pH of 5. What is the extent of ioniza...

    Text Solution

    |

  8. 50 ml of 0.1 M NH(4)OH, 25 ml of 2M NH(4)Cl were used to make a buffer...

    Text Solution

    |

  9. The pH of a buffer prepared by mixing 50 ml of 0.2 M CH(3)COOH and 25 ...

    Text Solution

    |

  10. 50 ml o 0.1 M sodium acetate, 25 ml of 0.2 M acetic acid were added to...

    Text Solution

    |

  11. When 20 ml of 0.1 MNH(4)OH are added to 20 ml of MNH(4)Cl solution, th...

    Text Solution

    |

  12. One litre of buffer solution contains 0.1 mole of acetic acid add 1 mo...

    Text Solution

    |

  13. 50 ml of 1 M CH(3)COOH solutioin, when added to 50 ml of 0.5 M NaOH g...

    Text Solution

    |

  14. The solibility product of Ag cl is 1.6xx10^(-10) "mol"^(2)//L^(2). Wha...

    Text Solution

    |

  15. The solubility product of Zr(OH)(2) is 4.5xx10^(-17) "mol"^(3)L^(-3). ...

    Text Solution

    |

  16. The solubility of Ag(2)CrO(4) is 1.3xx10^(-4) "mol"L^(-1). What is the...

    Text Solution

    |

  17. The solubility of A(2)B=2xx10^(-3) "mol" L^(-1). What is solubility pr...

    Text Solution

    |

  18. The solubility product of a salt AB=10^(-10) "mol"^(2)L^(-2). What is ...

    Text Solution

    |

  19. PQ and RS(2) are two sparingly soluble salts. Their solubility prodcts...

    Text Solution

    |

  20. In a 0.1 solution, acetic acid is 1.34% ionized. Calculate [H^(+)], [C...

    Text Solution

    |