State law of chemical equilibrium? What is `K_(c)` for the following equilibrium when the equilibrium concentration of each substance is `[SO_(2)]=0.60M,[O_(2)]=0.82M` and `[SO_(3)]=1.90M`
`2SO_(2)(g)+O_(2)(g)hArr2SO_(3)(g)`

Explanation

The ratio of product of molar concentrations of the products to the product of molar concentrations of the reactants has a constant value. This is known as the equilibrium law (or) law of chemi cal equilibrium.
Given equation is
`2SO_(2_((g)))+O_(2_((g))) hArr 2SO_(3_((g)))`
Given `[SO_(2)]=0.60M =[O_(2)]=0.82M, [SO_(3)]=1.90M`
`K_(c)=([SO_(3)]^(2+))/([SO_(2)]^(2)[O_(2)])=((1.9)^(2))/((0.6)^(2)(0.82))`
`=(3.61)/(0.36xx0.86)=(3.61)/(0.2952)`
`=12.22`