In how many ways can you express the strength of `H_(2)O_(2)`? Calculate the strength of 15 volume solution of `H_(2)O_(2)`. in `g//l`. Express the strength in normality and molarity.

Explanation

`to` Strength of `H_(2)O_(2)` can be expressed majorly in two ways.
`toH_(2)O_(2)` strength can be expressed in terms of i) Molarity ii) Normality.
Problem :
15 volume `H_(2)O_(2)` solution means 1 lit. of `H_(2)O_(2)` will give 15 lit. of `O_(2)` at STP.
`underset(68"gms")(2H_(2)O_(2))tounderset("22.4lit.")(O_(2)+H_(2)O)`
22.4 lit. of `O_(2)` produced from 68 gms of `H_(2)O_(2)`
15 lit. of `O_(2)` produced from x gms of `H_(2)O_(2)`
`x=(68xx15)/22.4=45.53"gms. of "H_(2)O_(2)`
`therefore` Strength of 15 volume `H_(2)O_(2)` = 45.53 gms/lit.
= `4.5%H_(2)O_(2)`
`to` Molarity of the 15 volume `H_(2)O_(2)` solution
= `(Wt)/(GMWxx1lit.)`
= `(45.53)/(34xx1)=1.339M`.
`to` Normality of the 15 volume `H_(2)O_(2)` solution
= `(Wt)/(GEWxx1lit)=(45.53)/(17xx1)=2.678N`.