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The vernier scale of an instrument has 5...

The vernier scale of an instrument has 50 divisions which coincide with 49 main scale divisions. If each main scale division is 0.5 mm, then using the instrument what would be the minimum inaccuracy in the measurement of distance?

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Value of each main scale division = 0.5 mm
No. of vernier scale divisions `" "`= 50
`" "` In vernier callipers, L.C = `S/N-"Value of one main scale division"/"No. of vernier scale divisions"`
`" "L.C.=(0.5)/50=0.01 m.m`
The minimum inaccuracy in the measurement of distance is 0.01 m.m.
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