One mole of an ideal gas at standard temperature and pressure occupies 22.4 L of (molar volume). What is the ratio of molar volume to the atomic volume of a mole of hydrogen ? (Take the sized of hydrogen molecule to about `1A^(@))`. Why is this ratio so large ?

Explanation

Atomic volume `=4/3piR^(3) times N`
`=4/3pi(0.5 times 10^(-10))^(3) times 6.023 times 10^(23)`
`=3.154 times 10^(-7)m^(3)`
Molar volume = 22.4 lit = `22.44 times 10^(-3) m^(3)`
`"Molar volume"/"Atomic volume"=(22.4 times 10^(-3))/(3.154 times 10^(-7))=7.1 times 10^(4)`
The ratio is large due to large intermolecular separations.