A bob of mass m is suspended by a light string of length L. It is imparted a horizontal velocity `v_(0)` at the lowest point A such that it completes a semicircular trajectory in the vertical plane with the string becoming slack only on reaching the topmost point, C this is shown in Fig. Obtain an expression for
the ratio of the kinetic energies `(K_(B)//K_(C))` at B and C. Comment on the nature of the trajectory of the bob after it reaches the point C .

Explanation

The ratio of the kinetic energies at Band C is :
`K_(B) = ((1)/(2) mv_(B)^(2))/((1)/(2)mv_(C)^(2))=(3)/(1)`
At point C, the string becomes slack and the velocity of the bob is horizontal and to the left