A body of mass 0.5 kg travels in a straight line with velocity `v = ax^(3//2)` where a `= 5m^(-1//2) s^(-1)` . What is the work done by the net force during its displacement from x = 0 to x = 2 m ?

Explanation

Here, m `= 0.5 kg, v = ax^(3//2) , a = 5m^(-1//2) s^(-1) w = ?`
Intial vel. at `x = 0, v_(1) = a xx 0 = 0 `
Final vel . at `x = 2, v_(2) = a2^(3//2) = 5 xx 2^(3//2)`
Workdone =increase in K.E `= (1)/(2) m`
`(v_(2)^(2) - v_(1)^(2) ) , W = (1)/(2) xx 0.5 [ (5 xx 2^(3//2))^(2) - 0] = 50 J`