A hunter aims a gun at a monkey hanging from a tree some distance away. The monkey drops from the branch at the moment he fires the gun hoping to avoid the bullet. Explain why the monkey made a wrong move.

Explanation

Suppose a hunter aims the sun at a monkey hanging from a high tree branch some distance away d. The instant the monkey observes the flash of the tree. No matter with what muzzle velocity the bullet is fired, it will hit the monkey.
Here the time taken by the monkey from the tree to the ground is `t_(1)=sqrt((2h)/g)" .....(1)"`
The path of bullet from the gun is like a horizontal Projectile, vertical velocity `u_(y)=0`, Let S = h. Let `t_(2)` be the time taken by the bullet to reach the ground.
`therefore S=ut+1/2at_(1)""^(2)`
`" "S=0 times t+1/2at_(2)""^(2)`
`therefore h=1/2gt_(2)""^(2)`
`t_(2)=sqrt((2h)/g)" ... (2)"`
It is observed from equation (1) and (2), `t_(1) = t_(2)`
Both bullet and monkey reach the ground simultaneously.
`therefore` As shown in fig. the bullet hits the monkey.
Therefore Monkey made a wrong move.