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A jet airplane travelling at the speed o...

A jet airplane travelling at the speed of `500 km h^(-1)` ejects its products of combustion at the speed of 1500 km h–1 relative to the jet plane. What is the speed of the latter with respect to an observer on the ground ?

Text Solution

Verified by Experts

ut `v_(p)` be the velocity of the products w.r.to ground
ut us consider the direction of motion of airplane to be positive direction of x-axis.
Here, speed of jet plane `v_(A)=500` km `h^(-1)`
Relative speed of products of combustion w.r.to jet plane `v_(rhoA)=-1500" km "h^(-1)`
Relative velocity of the products w.r.to air plane is
`v_(PA)=v_(P)-v_(A)=-1500`
`" (Or)"`
`v_(P)=v_(A)-1500=500-1500`
`" "=-1000" km "h^(-1)`
`" "` Here -ve sign shows the direction of products of combustion is opposite to that of airplane. Thus the magnitude of relative velocity is 1000 km `h^(-1)`.
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