Particle of masses 1g, 2g, 3g…. 100g are kept at the marks 1cm. 2cm, 3cm …. 1000cm respectively on 2 meter scale. Find the moment of inertia of the system of particles about a perpendicular bisector of the meter scale.

Explanation

By adding all the masses, we get M = 5050g
= 5.050 kg
= 5.1 kg
and L = 1m
M. I of the meter scale = `(5.1xx1^(2))/(12)`
`=0.425kg m^(2)`
`=0.43kg-m^(2)`