Determine the kinetic energy of a circular disc rotating with a speed of 60 rpm about an axis passing through a point on its circumference and perpendicular to its plane. The circular disc has a mass of 5kg and radius 1m.

Explanation

Here M = 5kg, R = 1m,
`omega=2pixx(N)/(t)=2pixx(60)/(60)rad//s=2pirad//s`
`I=(MR^(2))/(2)+MR^(2)=(3)/(2)MR^(2)`
`therefore` Kinetic energy = `(1)/(2)Iomega^(2)`
`=(1)/(2)xx(3)/(2)MR^(2)omega^(2)=(3)/(4)xx5xx(1)^(2)xx(2pi)^(2)`
`=(3)/(4)xx5xx4pi^(2)=15xx((22)/(7))^(2)`
`therefore` K.E= 148.16 J